QUESTION 81:
The network 172.25.0.0 has been divided into eight equal subnets. Which of the following IP addresses can be assigned to hosts in the third subnet if the ip subnet-zero command is configured on the router? (Choose three)
A. 172.25.78.243
B. 172.25.98.16
C. 172.25.72.0
D. 172.25.94.255
E. 172.25.96.17
F. 172.25.100.16
Explanation:
If we divide the address 172.25.0.0 in 8 subnets, the resulting subnets will be
1. 172.25.0.0
2. 172.25.32.0
3. 172.25.64.0 This is the third subnet
4. 172.25.96.0
5. 172.25.128.0
6. 172.25.160.0
7. 172.25.192.0
8. 172.25.224.0
Addresses that fall in the 3rd subnet will be from 172.25.64.0 ---- 172.25.95.255
Choices A, C and D lie in this network range.
QUESTION 82:
DRAG DROP
Certkiller has three locations and has plans to redesign the network accordingly. The networking team received 192.168.199.0 to use as the addressing for entire network from the administrator. After subnetting the address, the team is ready to assign the address.
The administrator plans to configure ip subnet-zero and use RIP v2 as the routing protocol. As a member of the networking team, you must address the network and at the same time converse unused addresses for future growth.
Being mindful of these goals, drag the host addresses on the left to the correct router interface. One of the routers is partially configured. Move the mouse over a router to view its configuration (** This information is missing**). Not all of the host 
Answer:
QUESTION 83:
DRAG DROP
Certkiller has three locations and has plans to redesign the network accordingly. The networking team received 192.168.197.0 to use as the addressing for entire network from the administrator. After subnetting the address, the team is ready to assign the address.
The administrator plans to configure ip subnet-zero and use RIP v2 as the routing protocol. As a member of the networking team, you must address the network and at the same time converse unused addresses for future growth.
Being mindful of these goals, drag the host addresses on the left to the correct router interface. One of the routers is partially configured. Move the mouse over a router to view its configuration (** This information is missing**). Not all of the host addresses on the left will be used.
Answer:
QUESTION 84:
DRAG DROP
Certkiller has three locations and has plans to redesign the network accordingly. The networking team received 192.168.15.0 to use as the addressing for entire network from the administrator. After subnetting the address, the team is ready to assign the address.
The administrator plans to configure ip subnet-zero and use RIP v2 as the routing protocol. As a member of the networking team, you must address the network and at the same time converse unused addresses for future growth.
Being mindful of these goals, drag the host addresses on the left to the correct router interface. One of the routers is partially configured. Move the mouse over a router to view its configuration (** This information is missing**). Not all of the host addresses on the left will be used.
Answer:
Exhibit:
Please study the exhibit carefully. All of the routers in the Certkiller network are configured with the "ip subnet-zero" command. Which network addresses should be used for Link A and Network A? (Choose two) Exhibit:
A. Link A - 172.16.3.0/30
B. Link A - 172.16.3.40/30
C. Network A - 172.16.3.128/25
D. Link A - 172.16.3.112/30
E. Network A - 172.16.3.48/26
F. Network A - 172.16.3.192/26
Explanation:
If a network address is subnetted, the first subnet obtained after subnetting the network address is called subnet zero.
Consider a Class B address, 172.16.0.0. By default the Class B address 172.16.0.0 has 16 bits reserved for representing the host portion, thus allowing 65534 (216-2) valid host addresses. If network 172.16.0.0/16 is subnetted by borrowing three bits from the host portion, eight (23) subnets are obtained. The table below is an example showing the subnets obtained by subnetting the address 172.16.0.0, the resulting subnet mask, the corresponding broadcast addresses, and the range of valid host addresses.
The class of the network subnetted and the number of subnets obtained after subnetting have no role in determining subnet zero. It is the first subnet obtained when subnetting the network address. Also, when you write the binary equivalent of the subnet zero address, all the subnet bits (bits 17, 18, and 19 in this case) are zeros. Subnet zero is also known as the all-zeros subnet.
In this example, link A will use the zero subnet of 172.16.30./30, while network A will need a /25 to support the 120 hosts. Answer C will support up to 128 (126 usable) hosts while options E and F will only support 62 usable IP addresses.
QUESTION 86:
A new subnet with 60 hosts has been added to the Certkiller network shown below.
Which subnet address should this network use to provide enough usable addresses while wasting the fewest addresses?
Exhibit:
A. 192.168.1.56/27
B. 192.168.1.64/26
C. 192.168.1.56/26
D. 192.168.1.64/27
Explanation:
A subnet mask of 255.255.255.192 (/26) will be needed to support 60 hosts. Option B will allow for this number of hosts, and the next available IP subnet in the 192.168.1.0 subnet that is not already used in the network is 192.168.1.64.
Incorrect Answers:
A, D: A /27 subnet mask will only support up to 30 hosts.
C: This network will conflict with the 192.168.1.48/28 network that is already in use, as the range of IP addresses used in this network is 192.168.1.48-192.168.1.63.
QUESTION 87:
In the Certkiller network shown below, which subnet address could a network administrator use for Network A on the left?
Exhibit:
A. 192.168.35.64/26
B. 192.168.35.32/27
C. 192.168.35.128/26
D. 192.168.35.192/27
E. 192.168.35.96/27
Explanation:
In order to support 62 hosts, a /26 will be needed, leaving only options A and C. The IP network in option A will conflict with the 192.168.35.64/28 that is already in use, leaving only choice C as the correct answer.
Incorrect Answers:
A: This will conflict with a network that is already in use, causing there to be duplicate IP addresses assigned in the network.
B, D, E: A /27 will only support 30 hosts.
QUESTION 88:
The Certkiller network administrator has designed the IP scheme as shown in the diagram below. What effect will this addressing scheme have on the network?
Exhibit:
A. IP traffic between subnet A and B will be prevented.
B. Routing information will not be exchanged.
C. The addressing scheme will allow all IP traffic between the LANs.
D. IP traffic between all the LANs will be prevented.
Explanation:
This scheme will allow for communication between all networks, and uses all IP addresses in the 192.168.1.0/24 IP network with no overlap. Note that RIPv2 is being used instead of RIPv1. RIPv2 carries subnet mask information allowing for VLSM networks like the one shown here.
QUESTION 89:
The network with the IP address 172.31.0.0/19 is to be configured on the Certkiller router with the partial configuration shown in the graphic. Which of the following statements describes the number of available subnets and hosts that will result from this configuration?
A. There are 7 usable subnets, with 2046 usable host addresses.
B. There are 8 usable subnets, with 30 usable host addresses.
C. There are 7 usable subnets, with 30 usable host addresses.
D. There are 8 usable subnets, with 2046 usable host addresses.
E. There are 7 usable subnets, with 8190 usable host addresses.
F. There are 8 usable subnets, with 8190 usable host addresses.
Explanation:
The 172.31.0.0/19 will have 3 bits in the network portion, and 13 bits in the host portion.
This will allow for 2^3 = 8 networks and 2^13 = 8192 hosts available for each network (8190 usable). Since the IP subnet-zero command is used the first network is available, making choice F correct.
QUESTION 90:
A new subnet with 12 hosts in the Certkiller network has been added. Which subnet address should this network use to provide enough useable addresses while wasting the fewest addresses?
Exhibit:
A. 192.168.10.80/29
B. 192.168.10.96/28
C. 192.168.10.80/28
D. 192.168.10.96/29
Explanation:
A /29 subnet mask will only support 6 IP hosts. A subnet mask of 255.255.255.240 (/28) will support up to 14 hosts, leaving only options B and C as viable. Option C will overlap with the existing 192.168.10.64/27 network, which will cause duplicate IP addresses to be assigned in the network.